Three beavers (one not shown) take turns biting a tree until it falls. The second beaver is twice as likely as the first to make the tree fall. The third is twice as likely as the second to make the tree fall. What is the probability that a bite taken by the third beaver causes the tree to fall?
A.
\(\frac{2}{7}\)
B.
\(\frac{1}{3}\)
C.
\(\frac{1}{7}\)
D.
\(\frac{4}{7}\)
Exam No：2018 First Round Grades 10-12 Year：2018 Question No：11
Answer:
D
Knowledge points:
G10-12 - Probability - Conditional Probability & Expected Value
Solution:
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