Tom mixes $$\(x \mathrm{~kg}\)$$ of cake mix that is $$\(10 \%\)$$ sugar with $$\(y \mathrm{~kg}\)$$ of cake mix that is $$\(20 \%\)$$ sugar. If the resulting mixture is $$\(z \%\)$$ sugar, then the ratio of $$\(x\)$$ to $$\(y\)$$ is
A.
\((20-z):(z-10)\)
B.
\((10-z):(z+20)\)
C.
\((z+10):(20-z)\)
D.
\((z+20):(10-z)\)
Exam No：2020 First Round Grades 10-12 Year：2020 Question No：11
Answer:
A
Knowledge points:
G10-12 - Algebra - Weighted Average & Ratios
Solution:
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