Two small smooth spheres $$\(A\)$$ and $$\(B\)$$, of equal radii and of masses $$\(\mathrm{km} \mathrm{kg}\)$$ and $$\(m \mathrm{~kg}\)$$ respectively, where $$\(k> 1\)$$, are free to move on a smooth horizontal plane. $$\(A\)$$ is moving towards $$\(B\)$$ with speed $$\(6 \mathrm{~m} \mathrm{~s}^{-1}\)$$ and $$\(B\)$$ is moving towards $$\(A\)$$ with speed $$\(2 \mathrm{~m} \mathrm{~s}^{-1}\)$$. After the collision $$\(A\)$$ and $$\(B\)$$ coalesce and move with speed $$\(4 \mathrm{~m} \mathrm{~s}^{-1}\)$$. Find, in terms of $$\(m\)$$, the loss of kinetic energy due to the collision. .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... .................................................................................................................................................... ....................................................................................................................................................

Mathematics
IGCSE&ALevel
CAIE
Exam No:9709_w21_qp_41 Year:2021 Question No:2(b)

Answer:

\(\mathrm{KE}\) initial \(=\frac{1}{2} \times k m \times 6^{2}+\frac{1}{2} \times m \times(-2)^{2}\)
\(\mathrm{KE}\) after \(=\frac{1}{2} \times(\mathrm{km}+m) \times 4^{2}\)
Loss of \(\mathrm{KE}=24 \mathrm{~m} \mathrm{~J}\)

Knowledge points:

4.5.2 understand the concepts of gravitational potential energy and kinetic energy, and use appropriate formulae

Solution:

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