With respect to the origin $$\(O\)$$, the points $$\(A\)$$ and $$\(B\)$$ have position vectors given by $$\(\overrightarrow{O A}=2 \mathbf{i}-\mathbf{j}\)$$ and $$\(\overrightarrow{O B}=\mathbf{j}-2 \mathbf{k}\)$$ Show that $$\(O A=O B\)$$ and use a scalar product to calculate angle $$\(A O B\)$$ in degrees. ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................ ........................................................................................................................................................
Exam No:9709_s21_qp_32 Year:2021 Question No:11(a)
Answer:
Show that \(O A=O B=\sqrt{5}\)
Evaluate the scalar product of the correct position vectors
Divide their scalar product by the product of the moduli of their vectors and evaluate the inverse cosine of the result
Obtain answer \(101.5^{\circ}\)
Evaluate the scalar product of the correct position vectors
Divide their scalar product by the product of the moduli of their vectors and evaluate the inverse cosine of the result
Obtain answer \(101.5^{\circ}\)
Knowledge points:
3.7.3 calculate the magnitude of a vector, and use unit vectors, displacement vectors and position vectors (In 2 or 3 dimensions.)
3.7.6 use formulae to calculate the scalar product of two vectors, and use scalar products in problems involving lines and points.
Solution:
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