$$\(4^{2 x}+4^{2 x}+4^{2 x}+4^{2 x}=\)$$
A.
\(2^{4 x}\)
B.
\(2^{4 x+2}\)
C.
\(4^{8 x}\)
D.
\(16^{2 x}\)
Exam No：2021 First Round Grade 7 Year：2021 Question No：27
Answer:
B
Knowledge points:
G7 - Algebra - Exponent Properties (Factoring & Basic Rules)
Solution:
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