$$\(2017^{2018} \times 2017^{2019}=2017^{?} \times 2017^{1009}\)$$

A.
1010
B.
2010
C.
3028
D.
4038
Mathematics
Competition
Math League
Exam No:2018 First Round Grade 5 Year:2018 Question No:28

Answer:

C

Knowledge points:

G5 - Number Theory - Powers & Exponents (Basic Rules)

Solution:

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