$$\(C D E F\)$$ is a cyclic quadrilateral and $$\(F C=F E\)$$. $$\(T U\)$$ is a tangent to the circle at $$\(C\)$$ and angle $$\(T C F=50^{\circ}\)$$. Find angle $$\(C D E\)$$. Angle $$\(C D E=\)$$ ............................................
Exam No:0580_w21_qp_43 Year:2021 Question No:2(b)(ii)
Answer:
\(100^{\circ}\)
Knowledge points:
E4.7.11 angles in opposite segments are supplementary; cyclic quadrilaterals
Solution:
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