$$\(A B D F\)$$ is a parallelogram and $$\(B C D E\)$$ is a straight line. $$\(A F=12 \mathrm{~cm}, A B=9 \mathrm{~cm}\)$$, angle $$\(C F D=40^{\circ}\)$$ and angle $$\(F D E=80^{\circ}\)$$. Explain why triangle $$\(C D F\)$$ is isosceles. ......................................................................................................................................... . .........................................................................................................................................
Exam No：0580_w20_qp_41 Year：2020 Question No：4(b)(ii)
Answer:
\(\angle \mathrm{CDF}=100\) leading to \(\angle D C F=40\)
Or
\(\angle \mathrm{EDF}=80\) leading to \(\angle D C F=40\)
'two equal angles'
Or
\(\angle \mathrm{EDF}=80\) leading to \(\angle D C F=40\)
'two equal angles'
Knowledge points:
E4.7.4 angle properties of triangles and quadrilaterals
Solution:
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