A student investigates a light-dependent resistor (LDR). The student assembles a series circuit consisting of a power supply, a switch, a $$\(470 \Omega\)$$ resistor and an LDR. The current $$\(I\)$$ in the circuit is calculated using the equation: $$\[ I=\frac{V_{X Y}}{R} \]$$ where $$\(R=470 \Omega\)$$. Use your voltmeter reading in (b)(ii) to calculate the current $$\(I\)$$. $$\[ I= \]$$ .....................................................

Physics
IGCSE&ALevel
CAIE
Exam No:0625_s25_qp_62 Year:2025 Question No:2(c)

Answer:



Knowledge points:

4.2.1.1 State that there are positive and negative charges

Solution:

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