A wire has original length $$$L$$$ and cross-sectional area $$$A$$$. A tensile force $$$F$$$ is applied to the wire which causes it to have extension $$$x$$$. The wire obeys Hooke's law. What is an expression for the Young modulus of the material from which the wire is made?

$\frac{\operatorname{stress} \times x}{L}$

$\frac{F}{A \times \operatorname{strain}}$

$\frac{F \times x}{A \times L}$

$\frac{\text { strain }}{\text { stress }}$

Physics

IGCSE&ALevel

CAIE

Exam No：9702_w24_qp_11 Year：2024 Question No：20

Answer:

Knowledge points:

6.1.1 appreciate that deformation is caused by a force and that, in one dimension, the deformation can be tensile or compressive

6.1.2 describe the behaviour of springs in terms of load, extension, elastic limit, Hooke’s law and the spring constant (i.e. force per unit extension)

6.1.3 define and use the terms stress, strain and the Young modulus

6.1.4 describe an experiment to determine the Young modulus of a metal in the form of a wire

A wire has original length $$\(L\)$$ and cross-sectional area $$\(A\)$$. A tensile force $$\(F\)$$ is applied to the wire which causes it to have extension $$\(x\)$$. The wire obeys Hooke's law. What is an expression for the Young modulus of the material from which the wire is made?

Answer:

Knowledge points:

Solution:

A wire has original length $$\(L\)$$ and cross-sectional area $$\(A\)$$. A tensile force $$\(F\)$$ is applied to the wire which causes it to have extension $$\(x\)$$. The wire obeys Hooke's law. What is an expression for the Young modulus of the material from which the wire is made?

Answer:

Knowledge points:

Solution:

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