The diagram shows two vessels, $$\(\mathrm{P}\)$$ and $$\(\mathrm{Q}\)$$, both with sides inclined at $$\(45^{\circ}\)$$ to the horizontal. Vessel $$\(P\)$$ tapers outwards and vessel $$\(Q\)$$ tapers inwards, as shown. Both vessels contain a liquid. The depth of the liquid in the vessels is the same. The liquid in vessel $$\(P\)$$ is twice as dense as the liquid in vessel $$\(Q\)$$. What is the ratio $$\(\frac{\text { pressure due to the liquid on the base of } P}{\text { pressure due to the liquid on the base of } Q} ?\)$$
A.
\( \frac{2}{1}\)
B.
\( \frac{\sqrt{2}}{1}\)
C.
\(\frac{1}{\sqrt{2}}\)
D.
\(\frac{1}{2}\)
Exam No:9702_w22_qp_12 Year:2022 Question No:16
Answer:
A
Knowledge points:
5.4.3 derive, from the definitions of pressure and density, the equation Δp = ρgDh
Solution:
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