The resistance of a lamp is $$\(10 \Omega\)$$ and the potential difference across it is 6.0 V .
A.
B.
C.
D.
Exam No：9702_s25_qp_14 Year：2025 Question No：29
Answer:
D
Knowledge points:
9.1.1 understand that electric current is a flow of charge carriers
9.1.2 understand that the charge on charge carriers is quantised
9.1.3 define the coulomb
9.1.4 recall and use Q = It
9.1.5 derive and use, for a current-carrying conductor, the expression I = Anvq, where n is the number density of charge carriers
Solution:
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