A block of mass $$\(m\)$$ is attached to a spring of force constant $$\(k\)$$. The mass is stretched a distance $$\(A\)$$ from equilibrium and released from rest. At a distance $$\(x\)$$ from the equilibrium position, which of the following represents the kinetic energy of the block?
A.
\(\frac{1}{2} k A^{2}-\frac{1}{2} k x^{2}\)
B.
\(\frac{1}{2} m A \sqrt{k / m}{ }^{2}\)
C.
\(\frac{1}{2} k A^{2}+\frac{1}{2} k x^{2}\)
D.
\(\frac{1}{2} k x^{2}\)
Exam No：AP Physics 1 Problem Set 1 Year：2024 Question No：APPhysics12024AP0204
Answer:
A
Knowledge points:
6.2 Energy of a Simple Harmonic Oscillator
Solution:
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