The registrar's office at a university has noticed that a large proportion of students fail to report a change of address. The registrar decides to take a random sample of 200 students and determine the number of students with the correct address on record. She finds that $$\(60 \%\)$$ of the students have the correct address on record. What would be the $$\(95 \%\)$$ confidence interval of the true proportion of students who have failed to report a change of address?
A.
\((0.543,0.657)\)
B.
\((0.532,0.668)\)
C.
\((0.511,0.689)\)
D.
\((0.343,0.457)\)
E.
\((0.332,0.468)\)
Exam No：AP Statistics Problem Set 11 Year：2024 Question No：31
Answer:
E
Knowledge points:
3.3 Random Sampling and Data Collection
5.5 Sampling Distributions for Sample Proportions
6.2 Constructing a Confidence Interval for a Population Proportion
Solution:
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